EasySQL challenge #4SELECTWHERECONCAT

Concatenate First and Last Name for Premium Users

Show each premium user as a single full_name column, with email and city.

The challenge runs on the SQLabHub practice database (SQLite) and uses the users table. You can solve it in the browser, with nothing to install.

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The task

List all premium users (is_premium = 1) showing their full name, email and city.

A correct answer returns 69 rows with 3 columns: full_name, email, city.

Tables used in this challenge

users 150 rows

id INTEGER (PK) · first_name TEXT · last_name TEXT · email TEXT · phone TEXT · city TEXT · country TEXT · created_at TEXT · status TEXT · is_premium INTEGER

First 3 rows of the users table
idfirst_namelast_nameemailphonecitycountrycreated_atstatusis_premium
1JenniferTorresjennifer.torres57@icloud.com+1-263-376-2371HoustonCanada2024-04-13active0
2DonnaAdamsdonna.adams52@gmail.com+1-753-780-6670Fort WorthCanada2020-09-15inactive0
3KennethYoungkenneth.young94@proton.me+1-440-743-9503AustinUSA2023-09-05active0

The first rows of each table are shown. See how all the tables relate on the database schema page.

Expected output

Expected output of the challenge
full_nameemailcity
Linda Allenlinda.allen39@yahoo.comSan Antonio
Brian Andersonbrian.anderson56@gmail.comSan Francisco
Thomas Bakerthomas.baker10@gmail.comPhoenix
Joseph Brownjoseph.brown39@proton.meFort Worth
Carol Browncarol.brown16@outlook.comDenver

First 5 of 69 rows. This is the output of the model solution on the practice database.

What you practise

  • Filtering rows with a WHERE condition
  • Building and cutting text values
  • Sorting the result with ORDER BY

Hint and approach

Try the challenge first. Open these only when you need them.

Show the hint

Use WHERE is_premium = 1

Show the step-by-step approach

How the model solution is built, in the order the database evaluates it:

  1. Read from the users table.
  2. Filter in WHERE: keep the rows where is_premium equals 1.
  3. Build full_name by joining text values with the || operator.
  4. Sort the result by last_name.

Model solution

Checking your session…

What to watch for

SQLite joins strings with the || operator; MySQL uses CONCAT() and SQL Server uses +. Remember the space literal between the two names, or they run together.

  • String functions. In SQLite and PostgreSQL, joining text with || returns NULL as soon as one of the parts is NULL.
  • ORDER BY. Without ORDER BY the row order is not guaranteed, even if it looks stable. Rows that tie on the sort columns can come back in any order.
  • WHERE. WHERE is evaluated before the SELECT list, so it cannot use a column alias defined there or the result of an aggregate.
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