Highest Avg Daily Revenue Users
Find users with highest average daily revenue.
The challenge runs on the SQLabHub practice database (SQLite) and uses the orders table. You can solve it in the browser, with nothing to install.
The task
Find users with highest average daily revenue.
A correct answer returns 114 rows with 2 columns: user_id, avg_daily.
Tables used in this challenge
orders 200 rows
id INTEGER (PK) · user_id INTEGER · total REAL · discount REAL · item_count INTEGER · status TEXT · order_date TEXT · shipped_date TEXT · shipping_city TEXT · shipping_country TEXT
| id | user_id | total | discount | item_count | status | order_date | shipped_date | shipping_city | shipping_country |
|---|---|---|---|---|---|---|---|---|---|
The first rows of each table are shown. See how all the tables relate on the database schema page.
Expected output
| user_id | avg_daily |
|---|---|
First 5 of 114 rows. This is the output of the model solution on the practice database.
What you practise
- Summarising many rows into one value with COUNT, SUM, AVG, MIN or MAX
- Grouping rows with GROUP BY to get one result row per group
- Grouping by more than one column to get a row per combination
- Querying the result of another query with a subquery in FROM
- Sorting the result with ORDER BY
Hint and approach
Try the challenge first. Open these only when you need them.
Show the hint
Group by user_id and order_date, then average
Show the step-by-step approach
How the model solution is built, in the order the database evaluates it:
- Build an inner query first (a derived table):
- Read from the
orderstable. - Group the rows by
user_idandorder_date, so the result has one row for each combination. - For each group, compute
SUM(total).
- Read from the
- Group the rows by
user_id, so the result has one row for each value. - For each group, compute
AVG(daily_total). - Sort the result by
avg_dailydescending.
Model solution
Checking your session…
What to watch for
- Derived table. Columns computed in the inner query are only visible outside under their alias, so every calculated column there needs a name.
- GROUP BY on several columns. Each extra GROUP BY column splits the groups further. Grouping by a column that is unique per row gives back one group per row.
- GROUP BY. Every selected column must either be in GROUP BY or sit inside an aggregate. SQLite accepts other columns and returns an arbitrary value for them; most databases raise an error.
Related SQL challenges
- Find Each Customer's Busiest Day by Order CountSimilar levelHard
- Measure Monthly Revenue Volatility per ProductSimilar levelHard
- Count Orders per Customer per Day with a Two-Column GROUP BYEasierMedium
- Find Products That Customers Buy More Than OnceSimilar levelHard
- Find the Week with the Highest RevenueSimilar levelHard
Keep learning
- Lesson: SQL Subqueries
- Lesson: GROUP BY Multiple Columns
- Lesson: GROUP BY
- Lesson: ORDER BY
- All SQL practice challenges, by difficulty and topic
- SQL interview questions with answers
- SQL Playground: run any query on the same database