Rank All Employees by Salary with RANK()
Return every employee with their company-wide salary rank, highest paid first.
The challenge runs on the SQLabHub practice database (SQLite) and uses the employees table. You can solve it in the browser, with nothing to install.
The task
Rank employees by salary globally.
A correct answer returns 120 rows with 13 columns: id, first_name, last_name, email, department, department_id, title, salary, hire_date, manager_id, city, status, rnk.
Tables used in this challenge
employees 120 rows
id INTEGER (PK) · first_name TEXT · last_name TEXT · email TEXT · department TEXT · department_id INTEGER · title TEXT · salary REAL · hire_date TEXT · manager_id INTEGER · city TEXT · status TEXT
| id | first_name | last_name | department | department_id | title | salary | hire_date | manager_id | city | status | |
|---|---|---|---|---|---|---|---|---|---|---|---|
The first rows of each table are shown. See how all the tables relate on the database schema page.
Expected output
| id | first_name | last_name | department | department_id | title | salary | hire_date | manager_id | city | status | rnk | |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
First 5 of 120 rows. This is the output of the model solution on the practice database. The task does not fix a sort order, so your rows may come back in a different order.
What you practise
- Ranking rows with RANK() or DENSE_RANK() and handling ties
Hint and approach
Try the challenge first. Open these only when you need them.
Show the hint
RANK()
Show the step-by-step approach
How the model solution is built, in the order the database evaluates it:
- Read from the
employeestable. - Rank the rows with
RANK(), ordered bysalarydescending. Tied rows share a rank and the next rank is skipped.
Model solution
Checking your session…
What to watch for
There is no PARTITION BY, so the ranking spans the whole table. RANK() leaves a gap after a tie (1, 1, 3). No two salaries are equal in this dataset, so the output matches what ROW_NUMBER() or DENSE_RANK() would give.
- RANK() and DENSE_RANK(). RANK() skips numbers after a tie (1, 1, 3) and DENSE_RANK() does not (1, 1, 2). Filtering on rank <= N returns more than N rows when there are ties.
Related SQL challenges
- Rank Orders by Total with DENSE_RANK()Similar levelHard
- Dense Rank Salaries Within Each DepartmentSimilar levelHard
- Rank Products by Total Units SoldSimilar levelHard
- Rank Products by Price Within Each CategorySimilar levelHard
- Find the Second Highest Salary in Each DepartmentSimilar levelHard
Keep learning
- Lesson: RANK & DENSE_RANK
- All SQL practice challenges, by difficulty and topic
- SQL interview questions with answers
- SQL Playground: run any query on the same database