Summarise Each Order: Total Quantity and Amount
Return one row per order with its total item quantity and total amount.
The challenge runs on the SQLabHub practice database (SQLite) and uses the order_items table. You can solve it in the browser, with nothing to install.
The task
Get total quantity and total amount per order.
A correct answer returns 200 rows with 3 columns: order_id, qty, amount.
Tables used in this challenge
order_items 496 rows
id INTEGER (PK) · order_id INTEGER · product_id INTEGER · quantity INTEGER · unit_price REAL · subtotal REAL
| id | order_id | product_id | quantity | unit_price | subtotal |
|---|---|---|---|---|---|
The first rows of each table are shown. See how all the tables relate on the database schema page.
Expected output
| order_id | qty | amount |
|---|---|---|
First 5 of 200 rows. This is the output of the model solution on the practice database. The task does not fix a sort order, so your rows may come back in a different order.
What you practise
- Summarising many rows into one value with COUNT, SUM, AVG, MIN or MAX
- Grouping rows with GROUP BY to get one result row per group
Hint and approach
Try the challenge first. Open these only when you need them.
Show the hint
SUM(quantity), SUM(subtotal)
Show the step-by-step approach
How the model solution is built, in the order the database evaluates it:
- Read from the
order_itemstable. - Group the rows by
order_id, so the result has one row for each value. - For each group, compute
SUM(quantity)andSUM(subtotal).
Model solution
Checking your session…
What to watch for
The amounts come from summing order_items.subtotal. In this practice dataset they do not match orders.total, because the two tables were generated independently; do not expect them to reconcile.
- GROUP BY. Every selected column must either be in GROUP BY or sit inside an aggregate. SQLite accepts other columns and returns an arbitrary value for them; most databases raise an error.
- Aggregate functions. Aggregates skip NULLs. AVG divides by the number of non-NULL values and COUNT(column) can be smaller than COUNT(*).
Related SQL challenges
- Find the Last Order Date for Each CustomerSimilar levelMedium
- Find the Best-Selling Products by QuantitySimilar levelMedium
- Total Sales per Order Status with SUM and GROUP BYEasierEasy
- Rank Products by Their Average Review RatingHarderHard
- Count Employees in Each DepartmentEasierEasy
Same technique, other tables
More practice on this pattern with different columns:
Keep learning
- Lesson: GROUP BY
- Lesson: Aggregate Functions
- All SQL practice challenges, by difficulty and topic
- SQL interview questions with answers
- SQL Playground: run any query on the same database