MediumSQL challenge #133GROUP BYORDER BY

Users with Most Reviews

Find users who have written the most reviews.

The challenge runs on the SQLabHub practice database (SQLite) and uses the reviews table. You can solve it in the browser, with nothing to install.

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The task

Find users who have written the most reviews.

A correct answer returns 104 rows with 2 columns: user_id, review_count.

Tables used in this challenge

reviews 180 rows

id INTEGER (PK) · product_id INTEGER · user_id INTEGER · rating INTEGER · comment TEXT · reviewed_at TEXT · helpful_votes INTEGER

First 3 rows of the reviews table
idproduct_iduser_idratingcommentreviewed_athelpful_votes
123455Works perfectly. Very happy with this purchase.2022-09-0240
2101685Excellent build quality. Will buy again!2023-01-0596
340391Would give 6 stars if I could!2023-05-1517

The first rows of each table are shown. See how all the tables relate on the database schema page.

Expected output

Expected output of the challenge
user_idreview_count
1505
1274
944
654
364

First 5 of 104 rows. This is the output of the model solution on the practice database.

What you practise

  • Summarising many rows into one value with COUNT, SUM, AVG, MIN or MAX
  • Grouping rows with GROUP BY to get one result row per group
  • Sorting the result with ORDER BY

Hint and approach

Try the challenge first. Open these only when you need them.

Show the hint

GROUP BY user_id ORDER BY COUNT DESC

Show the step-by-step approach

How the model solution is built, in the order the database evaluates it:

  1. Read from the reviews table.
  2. Group the rows by user_id, so the result has one row for each value.
  3. For each group, compute COUNT(*).
  4. Sort the result by review_count descending.

Model solution

Checking your session…

What to watch for

  • GROUP BY. Every selected column must either be in GROUP BY or sit inside an aggregate. SQLite accepts other columns and returns an arbitrary value for them; most databases raise an error.
  • ORDER BY. Without ORDER BY the row order is not guaranteed, even if it looks stable. Rows that tie on the sort columns can come back in any order.
  • Aggregate functions. Aggregates skip NULLs. AVG divides by the number of non-NULL values and COUNT(column) can be smaller than COUNT(*).
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